Ok, so
Remember that if we got the slope of the line and a point of it, we could use the following formula:
[tex]y=y_1+m(x-x_1)[/tex]Where (x1,y1) is a point and m is the slope.
If we replace our values:
[tex]\begin{gathered} y=4+\frac{3}{4}(x-(-12)) \\ \\ y=4+\frac{3}{4}(x+12) \\ \\ y=4+\frac{3}{4}x+\frac{36}{9} \\ \\ y=4+\frac{3}{4}x+4 \\ \\ y=\frac{3}{4}x+8 \end{gathered}[/tex]Therefore, the equation of this line will be:
y=3/4x+8