Answered

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Please help me solve the equation on the interval shown in the picture. Must show work.

Please Help Me Solve The Equation On The Interval Shown In The Picture Must Show Work class=

Sagot :

Answer:

Given that,

[tex]1-\sin\theta=0\text{ for an interval of }\theta\text{ is 0}\leq\theta\leq2\pi[/tex]

On solving this we get,

[tex]\sin\theta=1[/tex]

we get,

[tex]\theta=\frac{\pi}{2}[/tex]

Since the period of sin theta is 2 pi.

The solution of the given equation is,

[tex]\theta=\frac{\pi}{2}[/tex]
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