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Sagot :
Given that Fred can swim 60 laps in 100 minutes.
Let's find the number of laps he can swim in 40 minutes.
60 laps = 100 minutes
x laps = 40 minutes
Where x represents the number of laps he could swim in 40 minutes.
Let's solve for x.
Therefore, we have:
[tex]\begin{gathered} \frac{100}{60}=\text{ }\frac{40}{x} \\ \\ 100x\text{ = }2400 \\ \\ x\text{ = }\frac{2400}{100}\text{ = 24} \end{gathered}[/tex]Therefore, in 40 minutes, Fred can swim 24 laps
ANSWER:
24 laps
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