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Sagot :
The slope of a line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]The point-slope form of a line is:
[tex]y-y_1=m(x-x_1_{})[/tex]7) The line passes through (0,-2) and (3,2)
Slope:
[tex]m=\frac{2-(-2)}{3-0}=\frac{4}{3}[/tex]Equation:
y - 2 = 4/3(x - 3)
8) The line passes through (0,5) and (4,3)
Slope:
[tex]m=\frac{3-5}{4-0}=-\frac{2}{4}=-\frac{1}{2}[/tex]Equation:
y - 3 = -1/2(x - 4)
9) this line is parallel to the y-axis, then it has the form:
x = constant
In this case, the equation is:
x = 1
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