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Sagot :
The mean of the data set is given by the sum of all travel times divided by te total amount of students. Therefore:
[tex]\begin{gathered} \operatorname{mean}=\frac{5+13+13+6+8+11}{6} \\ =\frac{56}{6}=9.333\ldots \end{gathered}[/tex]Rounding to the nearest tenth, the mean of the travel times is 9.3.
The median of the data set is equal to te mean of the two central values if the amount of data is an even number, and it's equal to the central value if the amount of data is an odd number.
Order the data set from lower to greater travel times:
[tex]5,6,8,11,13,13[/tex]The two central values are 8 and 11, so the median will be the average of 8 and 11:
[tex]\operatorname{median}=\frac{8+11}{2}=\frac{19}{2}=9.5[/tex]Therefore, the median of the travel times is 9.5
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