Answered

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A 3 kg hard steel ball collides head-on with a 1 kg hard steel ball. The balls are moving up at 2 m/s in opposite directions before they collide. Upon colliding, the 3 kg ball stops. What is the velocity of the 1 kg object after the collision?

Sagot :

We know that the momentum is conserved this means that:

[tex]p_{1i}+p_{2i}=p_{1f}+p_{2f}[/tex]

where

[tex]p=mv[/tex]

In this case the balls are moving opposite each other this means that the velocities have opposite sign, we also know that the 3 kg ball stops after the collision this means that it final velocity is zero, then we have:

[tex]\begin{gathered} (3)(2)-(1)(2)=(3)(0)+1v_{2f} \\ 6-2=v_{2f} \\ v_{2f}=4 \end{gathered}[/tex]

Therefore the velocity of the 1 kg ball after the collision is 4 m/s

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