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Sagot :
Given the following inequality:
[tex]2z-2\leqslant-8[/tex]We will solve the inequality as follows:
First, add 2 to both sides
[tex]\begin{gathered} 2z-2+2\leqslant-8+2 \\ 2z\operatorname{\leqslant}-6 \end{gathered}[/tex]Second, divide both sides by 2
[tex]\begin{gathered} \frac{2z}{2}\operatorname{\leqslant}\frac{-6}{2} \\ \\ z\operatorname{\leqslant}-3 \end{gathered}[/tex]So, the answer will be, the solution using interval notation is as follows:
[tex](-\infty,-3][/tex]
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