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2z - 2 <= - 8 Step 1 of 2: Write the solution using interval notation

Sagot :

Given the following inequality:

[tex]2z-2\leqslant-8[/tex]

We will solve the inequality as follows:

First, add 2 to both sides

[tex]\begin{gathered} 2z-2+2\leqslant-8+2 \\ 2z\operatorname{\leqslant}-6 \end{gathered}[/tex]

Second, divide both sides by 2

[tex]\begin{gathered} \frac{2z}{2}\operatorname{\leqslant}\frac{-6}{2} \\ \\ z\operatorname{\leqslant}-3 \end{gathered}[/tex]

So, the answer will be, the solution using interval notation is as follows:

[tex](-\infty,-3][/tex]

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