Answered

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please help ASAP!!!!

Sagot :

The question is to divided ;

6y^2 -11 y +15 by 2y + 7

Performing long division, starting by 6y^2 and 2y to get ;

3y

Perform product -----[3y {2y+7}] ------6y^2 +21 ---------a)

Cancel the 6y^2 terms by subtaction.This means subtact 6y^2 +21 from 6y^2-11y +7

This will give : -32y +7 -----------b)

Then proceed with division : Divide - 32y + 7 by 2y +7

This will give:

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