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If 18 g of a radioactive substance are present initially and 8 yr later, only 9 g remain, how much substance will be present after 12 yr?

If 18 G Of A Radioactive Substance Are Present Initially And 8 Yr Later Only 9 G Remain How Much Substance Will Be Present After 12 Yr class=

Sagot :

Step 1: we have to obtain the number of grams lost by the radioactive substance every year.

For an 18g radioactive substance,

If 9g remains after 8years, this implies that:

[tex]\frac{9}{8}\text{ grams = 1.125g of the radioactive substance is lost every year}[/tex]

The number of years left to complete 12years after the 8years period is 4 years.

Since 1.125g of the radioactive substance is lost every year, this implies that:

[tex]1.125g\text{ x 4 = 4.5g will be lost for the remaining 4years period}[/tex]

Therefore, the total loss for the 12 years period is :

[tex]9g+4.5g\text{ = 13.5g}[/tex]

The amount of substance that will be left after 12years is:

[tex]18g-13.5g=4.500g[/tex]

Hence, after 12years, 4.500g of the radioactive substance will be left.

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