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Sagot :

In simple interest, we can use the formula:

[tex]I=P\cdot r\cdot t[/tex]

Where P is the principal value, that is, the value of the loan, $9000; r is the annual rate and t is the period of loan in years.

We know Rita paid interest of $336, so

[tex]I=336[/tex]

However, the period that she had is not in years, it is in months. However, in simple interest we can just convert "t" from year to months. If she got 7 months, this is equivalent of 7/12 years, because one year has 12 months.

Thus, t = 7/12

Now, we know "I", "P" and "t", we can substitute and solve for "r":

[tex]\begin{gathered} 336=9000\cdot r\cdot\frac{7}{12} \\ \frac{336}{9000}=r\cdot\frac{7}{12} \\ 0.037333\ldots=r\cdot\frac{7}{12} \\ r=\frac{12}{7}\cdot0.037333\ldots \\ r=\frac{0.448}{7}=0.064 \end{gathered}[/tex]

In percentage, we have 6.4% of annual interest.