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Sagot :
Answer
0.46 J/g°C
Explanation
Given:
Mass of iron, m = 15.75 g
Quantity of heat, q = 1086.75 J
Initial temperature, T₁ = 25.0 °C
Final temperature, T₂ = 1750 °C
What to find:
The specific heat capacity, c of the iron.
Step-by-step solution:
The specific heat capacity of the iron can be calculated using the formula below:
[tex]q=mc(T_2-T_1)[/tex]Put the values of the given parameters into the formula:
[tex]\begin{gathered} 1086.75=15.75\times c\times(175.0-25.0) \\ \\ 1086.75=15.75\times c\times150 \\ \\ 1086.75=2362.5c \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }2362.5 \\ \\ \frac{1086.75}{1362.5}=\frac{2362.5c}{2362.5} \\ \\ c=0.46\text{ }J\text{/}g^0C \end{gathered}[/tex]The specific heat capacity, c of the iron = 0.46 J/g°C
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