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7(6)^×=39How do I solve for x?

Sagot :

Given:

[tex]7(6)^x=39[/tex]

Required:

We need to find the value of x.

Explanation:

Divide both sides of the equation by 7.

[tex]\frac{7(6)^x}{7}=\frac{39}{7}[/tex][tex](6)^x=\frac{39}{7}[/tex]

Take a natural log on both sides of the equation.

[tex]In(6)^x=In(\frac{39}{7})[/tex][tex]Use\text{ }In(a)^n=nIn(a).[/tex][tex]xIn(6)=In(\frac{39}{7})[/tex][tex]Divide\text{ both sides of the equation by }In(6).[/tex][tex]\frac{xIn(6)}{In(6)}=\frac{In(39\/7)}{In(6)}[/tex][tex]x=\frac{In(39\/7)}{In(6)}[/tex][tex]x=0.9587[/tex][tex]x=0.96[/tex]

Final answer:

[tex]x=0.9587[/tex][tex]x=0.96[/tex]