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Sagot :
Answer:
9.14moles
Explanations:
According to the Avogadro's constant,
[tex]1mole\text{ of }C_4H_{10}=6.02\times10^{23}molecules[/tex]We are to determine the moles of 5.50 x 10^24 molecules of butane. This is expressed as:
[tex]\begin{gathered} mole\text{ of }C_4H_{10}=\frac{5.50\times10^{24}}{6.02\times10^{23}} \\ mole\text{ of C}_4H_{10}=0.914\times10^{24-23} \\ mole\text{ of C}_4H_{10}=0.914\times10 \\ mole\text{ of C}_4H_{10}=9.14moles \end{gathered}[/tex]Therefore the required mole of butane is 9.14moles
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