The Solution:
Given:
Find angle 1 and angle 2.
By Trigonometric Ratio:
Step 1:
[tex]\begin{gathered} \sin\angle1=\frac{opposite}{hypotenuse} \\ \\ \sin\angle1=\frac{3}{5} \\ By\text{ inverse Trig ratio,} \\ \angle1=\sin^{-1}(\frac{3}{5})=36.87^o \end{gathered}[/tex]
Step 2:
[tex]\begin{gathered} \sin\angle2=\frac{4}{5} \\ \\ By\text{ inverse Trig. Ratio,} \\ \\ \angle2=\sin^{-1}(\frac{4}{5})=53.13^o \end{gathered}[/tex]
Therefore, the correct answers are:
[tex]\begin{gathered} \angle1=36.87^o \\ \\ \angle2=53.13^o \end{gathered}[/tex]
