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how many moles of O2, will be needed to burn 3.7 moles of CHA? CHA+30-->2C02+ 2 H20

Sagot :

In this question, we have to find the number of moles needed of CH4 to burn 3.7 moles O2, and we can do that by looking at their molar ratio:

CH4 + 3 O2 -> 2 CO2 + 2 H2O

The molar ratio between CH4 and O2 is 1:3, which means that we need 1 mol of CH4 for every 3 moles of O2, therefore if we have 3.7 moles of O2, we will need:

1 CH4 = 3 O2

x CH4 = 3.7 O2

3x = 3.7

x = 3.7/3

x = 1.23 moles of CH4 are required

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