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I need a help!Please solve this question r2+200r-323 = 0

Sagot :

Given:

[tex]r^2+200r-323=0[/tex][tex]a=1\text{ ; b=200 ; c=-323}[/tex][tex]r=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex][tex]r=\frac{-200\pm\sqrt[]{200^2-4(1)(-323)}}{2(1)}[/tex][tex]r=\frac{-200\pm\sqrt[]{400^{}+1292}}{2}[/tex][tex]r=\frac{-200\pm\sqrt[]{400^{}+1292}}{2}[/tex][tex]r=\frac{-200\pm\sqrt[]{1692}}{2}[/tex][tex]r=\frac{-200\pm\sqrt[]{2^2\times3^2\times47}}{2}[/tex][tex]r=\frac{-200\pm6\sqrt[]{47}}{2}[/tex][tex]r=\frac{2(-100\pm3\sqrt[]{47})}{2}[/tex][tex]r=-100\pm3\sqrt[]{47}[/tex][tex]r=-100+3\sqrt[]{47}\text{ ,}-100-3\sqrt[]{47}[/tex]

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