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Sagot :
Explanation:
To solve this exercise and find the volume in mL of KOH, the first step is to know how to write the equation that represents the neutralization reaction that took place and balance it correctly. Neutralization reactions follow the following scheme: acid + base → salt + water.
In this case, the following reaction occurred:
2 KOH (aq) + H2SO4 (aq) → K2SO4 (aq) + 2 H2O (l)
The second step is to relate the obtained data. Since a total neutralization reaction took place, this means that the number of H+ ions and OH- ions present in the medium became equal. So we have:
2nH2SO4 = nKOH
Knowing that n = M . V, we can perform the following substitution:
nH2SO4 = nKOH
2 * MH2SO4 * H2SO4 = MKOH * VKOH
2 * 0.425 * 8 = 0.220 * VKOH
VKOH = 30.9 mL
Answer: 30.9 ml of KOH solution
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