Answered

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A box of weight W = 500 N is set on a light plank d = 5 meters from a fulcrum. A force F is applied to the plank on the opposite side of the fulcrum a distance D = 10 meters from the fulcrum, as shown. What minimum force is required to lift the box?

A Box Of Weight W 500 N Is Set On A Light Plank D 5 Meters From A Fulcrum A Force F Is Applied To The Plank On The Opposite Side Of The Fulcrum A Distance D 10 class=

Sagot :

Given data

*The weight of the box is W = 500 N

*The distance of the plank from the fulcrum is d = 5 m

*The given force at a distance from the fulcrum is D = 10 m

The minimum force is required to lift the box is given by the net torque as

[tex]\begin{gathered} \tau=0 \\ W\times d-F\times D=0 \\ W\times d=F\times D \end{gathered}[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} 500\times5=F\times10 \\ F=250\text{ N} \end{gathered}[/tex]

Hence, the minimum force is required to lift the box is F = 250 N

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