Answered

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Two capacitors of 4 μF and 8 μF are connected in parallel. What is the equivalent capacitance of this system?3 μF17 μF12 μF9 μF

Sagot :

[tex]12\mu F[/tex]

Explanation

The equivalent capacitance of two capacitors connected in parallel is the sum of the individual capacitances.

[tex]C_{eq}=C_1+C_2[/tex]

Step 1

Let

[tex]\begin{gathered} C_1=4\mu F \\ C_2=8\mu F \end{gathered}[/tex]

hence

[tex]\begin{gathered} C_{eq}=C_1+C_2 \\ C_{eq}=4\mu F+8\mu F \\ C_{eq}=12\mu F \end{gathered}[/tex]

therefore, the answer is

[tex]12\mu F[/tex]

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