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Sagot :
Two trains leave towns 831 kilometers apart at the same time and travel toward each other.
Distance = d = 831 km
One train travels 15 km/h faster than the other.
Let the speed of the slower train is x km/h
Then the speed of the faster train is (x + 15) km/h
If they meet in 3 hours what is the rate of each train?
Time = t = 3 hours
Recall that the relationship between speed, distance, and time is given by
[tex]d=s\cdot t[/tex]So we can write
[tex]831=(x+x+15)\cdot3_{}[/tex]Where x is the speed of the slower train and x+15 is the speed of the faster train.
Let us solve the above equation
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