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Sagot :
Solution:
Given:
[tex]\begin{gathered} f(x)=profits \\ x=price\text{ of pens} \end{gathered}[/tex]From the graph, the x-intercept exists at (0,0) and (6,0).
The maximum value is (3,120).
The x-intercept represents the break-even points. The company was not in profit or loss when no pen was sold and when 6 pens were sold, the profit was $0 at these two points.
The maximum value of the graph represents the maximum profit made by the company. The company made a maximum profit of $120 when 3 pens were sold.
The interval where the function is increasing is from negative infinity to x = 3. This shows that the more pen sold, the higher the profit made.
The interval where the function is decreasing is from x = 3 to positive infinity. This shows that the less pen sold, the lower the profit made.
The approximate average rate of change of the graph from x = 3 to x = 5 is;
[tex]\begin{gathered} ARC=\frac{f(x_2)-f(x_1)}{x_2-x_1} \\ where: \\ x_1=3 \\ x_2=5 \\ f(x_1)=120 \\ f(x_2)=60 \\ \\ Hence, \\ ARC=\frac{60-120}{5-3} \\ ARC=\frac{-60}{2} \\ ARC=-30 \end{gathered}[/tex]The rate represents a decrease of $30 for every pen sold across the decreasing interval.
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