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A 20.0 kg bumper car moving to the left with a velocity of 6.0 m/s, collides head-on with a 30.0 kg bumper car that is stationary. If the first bumper car comes to a complete stop after the collision, what is the velocity of the larger bumper car after the collision?1.6 m/sZero, the second bumper car is too heavy to move.4.0 m/s6.0 m/s

Sagot :

Let velocity of larger car = v;

mass of larger car = 30 kg;

mass of smaller car = 20 kg

velocity of smaller car = 6.0 m/s

Now according to law of conservation of momentum---

[tex]m_1v_1=\text{ - m}_2\text{v}_2;[/tex]

using this formula ,we get

[tex]\begin{gathered} 30\times v=\text{ - 20}\times6; \\ \therefore\text{ v = -}\frac{120}{30}\text{ = -4 m/s} \end{gathered}[/tex]

Therefore velocity of larger car after collision is 4 m/s in opposite direction of smaller car .

Final answer is 4.0 m/s

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