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Sagot :
Let velocity of larger car = v;
mass of larger car = 30 kg;
mass of smaller car = 20 kg
velocity of smaller car = 6.0 m/s
Now according to law of conservation of momentum---
[tex]m_1v_1=\text{ - m}_2\text{v}_2;[/tex]using this formula ,we get
[tex]\begin{gathered} 30\times v=\text{ - 20}\times6; \\ \therefore\text{ v = -}\frac{120}{30}\text{ = -4 m/s} \end{gathered}[/tex]Therefore velocity of larger car after collision is 4 m/s in opposite direction of smaller car .
Final answer is 4.0 m/s
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