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An ideal spring has a spring constant k = 26.2 N/m. What is the amount of work that must be done to stretch the spring 0.520 m from its relaxed length?

Sagot :

Given data:

* The spring constant of the spring is k = 26.2 N/m.

* The change in the length of the spring is x = 0.520 m.

Solution:

The work done to stretch the spring is,

[tex]W=\frac{1}{2}kx^2[/tex]

Substituting the known values,

[tex]\begin{gathered} W=\frac{1}{2}\times26.2\times(0.520)^2 \\ W=3.54\text{ J} \end{gathered}[/tex]

Thus, the amount of work done is 3.54 J.

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