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Sagot :
Logarithmic equations
We know that the following relation is satisfied:
[tex]\begin{gathered} \log _ab=c \\ a^c=b \end{gathered}[/tex]We use this relation in the given formula:
[tex]\begin{gathered} \log _2(3x-8)=6 \\ \downarrow \\ 2^6=3x-8 \end{gathered}[/tex]Using this equation we can find x:
[tex]\begin{gathered} 2^6=3x-8 \\ \downarrow \\ 64=3x-8 \\ \downarrow \\ 64+8=3x \\ 72=3x \\ \frac{72}{3}=x \\ 24=x \end{gathered}[/tex]Answer: x = 24
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