ANSWER:
0.839 milliTeslas
STEP-BY-STEP EXPLANATION:
Given:
Current (I) = 51.471 A
Distance (d) = 1.227 cm = 0.01227 m
Current solenoid (Is) = 16.358 A
Distance solenoid (ds) =65.271 cm = 0.65271 m
A sketch of the situation:
We calculate the magnetic field for each case:
[tex]\begin{gathered} B_w=\frac{\mu_0\cdot I}{2\pi d}=\frac{4\pi\cdot10^{-7}\cdot51.471}{2\pi\cdot0.01227}=0.00083897\text{ T} \\ \\ B_s=\frac{\mu_0\cdot I_s}{2\pi\cdot d_s}=\frac{4\pi\cdot10^{-7}\cdot16.358}{2\pi\cdot0.65271}=0.00000501\text{ T} \end{gathered}[/tex]Therefore, the resulting field due to the wire and the solenoid would be:
[tex]\begin{gathered} B=\sqrt{(B_w)^2+(B_s)^2} \\ \\ \text{ We replacing:} \\ \\ B=\sqrt{(0.00083897)^2+(0.00000501)^2} \\ \\ B\cong0.000839\text{ T}=0.839\text{ mT} \end{gathered}[/tex]The correct answer is 0.839 milliTeslas
