At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let the number of dimes = x
And the number of nickels = y
There are 8 more dimes than nickels.
So, x = y + 8
The jar of nickels and dimes contains $5.45
So, the total amount of money = 545 cents
dime = 10 cents
nickel = 5 cents
so, 10x + 5y = 545
so, we have the following system of equations:
[tex]\begin{gathered} x=y+8\rightarrow(1) \\ 10x+5y=545\rightarrow(2) \end{gathered}[/tex]Substitute with x from equation (1) into equation (2) then solve for y
[tex]\begin{gathered} 10(y+8)+5y=545 \\ 10y+80+5y=545 \\ 15y=545-80 \\ 15y=465 \\ \\ y=\frac{465}{15}=31 \\ x=31+8=39 \end{gathered}[/tex]So, the number of dimes = 39
The number of nickels = 31
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
