Answered

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Find the standard deviation for the following group of data items. Round your answer to the nearest tenth (or one decimal place). 8, 9, 12, 15, 18, 21, 22

Sagot :

we must use the formula

[tex]\sqrt[]{\frac{\sum^N_i(x_i-X)^2}{N}}[/tex]

where N is the total of numbers xi each value and X the average

CALCULATIONS

X

[tex]X=\frac{8+9+12+15+18+21+22}{7}=15[/tex]

Sum of (xi-X)

[tex]\begin{gathered} x1=8-15=-7 \\ x2=9-15=-6 \\ x3=12-15=-3 \\ x4=15-15=0 \\ x5=18-15=3 \\ x6=21-15=6 \\ x7=22-15=7 \end{gathered}[/tex][tex]x1+x2+x3+x4+x5+x6+x7=0[/tex]

STANDARD DEVIATION

[tex]\sqrt[]{\frac{0}{7}}=0[/tex]

THE STANDARD DEVIATION IS 0

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