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Sagot :
The formula of the area of a circle is as follows:
[tex]A=\pi r^2[/tex]Since the diameter is twice the radius, we may rewrite the equation as follows:
[tex]A=\pi\mleft(\cfrac{d}{2}\mright)^2[/tex]where d is the diameter.
Thus, the area of Circle A is as follows:
[tex]\begin{gathered} A_{CircleA}=\pi\mleft(\cfrac{12}{2}\mright)^2 \\ =\pi(6)^2 \\ =\pi(36) \\ \approx(3.14)(36) \\ \approx113.04 \\ \approx113 \end{gathered}[/tex]The area of Circle B is as follows:
[tex]\begin{gathered} A_{CircleB}=\pi\mleft(\cfrac{5}{2}\mright)^2 \\ =\pi(2.5)^2 \\ =\pi(6.25) \\ \approx(3.14)(6.25) \\ \approx19.625 \\ \approx20 \end{gathered}[/tex]The area of Circle C is as follows:
[tex]\begin{gathered} A_{\text{Circle C}}=\pi\mleft(\cfrac{24.8}{2}\mright)^2 \\ =\pi(12.4)^2 \\ =\pi(153.76) \\ \approx(3.14)(153.76) \\ \approx482.8064 \\ \approx483 \end{gathered}[/tex]
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