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Sagot :
Given:
The perimeter of a rectangle is 44 meters.
The length is 10 meters more than twice the width.
Required:
To find the dimensions.
Explanation:
The perimetero of rectangle formula is
[tex]P=2(L+W)[/tex]Let x be the width.
The length is 10 meters more than twice the width.
So
[tex]L=2x+10[/tex]Now
[tex]\begin{gathered} P=2(2x+10+x) \\ \\ 44=4x+20+2x \\ \\ 44=6x+20 \\ \\ 6x=44-20 \\ \\ 6x=24 \\ \\ x=\frac{24}{6} \\ \\ x=4m \end{gathered}[/tex]Here the width is 4m.
Now the length is
[tex]\begin{gathered} L=2(4)+10 \\ =8+10 \\ =18m \end{gathered}[/tex]Final Answer:
18 meters and 4 meters.
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