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Sagot :
Answer:
The equation of the line with the given points is:
[tex]y=-\frac{1}{5}x[/tex]Explanation:
Given the coordinates (0, 0) and (10, -2)
The equation of a line is in the form:
y = mx + b
Where m is the slope and b is the y-intercept.
The slope from the given coordinates is:
[tex]\begin{gathered} m=\frac{-2-0}{10-0} \\ \\ =-\frac{2}{10}=-\frac{1}{5} \end{gathered}[/tex]The equation is now in the form:
[tex]y=-\frac{1}{5}x+b[/tex]Using the point (10, -2) to find b, replace x by 10 and y by -2 in the last equation
[tex]\begin{gathered} -2=-\frac{1}{5}(10)+b \\ \\ -2=-2_{_{_{_{_{_{_{_{}}}}}}}}+b \\ b=0 \end{gathered}[/tex]Therefore, the equation of the line is:
[tex]y=-\frac{1}{5}x[/tex]
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