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Sagot :
We need to find which function doesn't have a domain for all real numbers.
for a.
[tex]f(x)=\sqrt[]{x}-1[/tex]When we have a square root " The domain is all values of x results in a radicand that is equal to greater than zero"
So the domain, in this case, is x≥0.
b.
[tex]-x^3+4x[/tex]x can take any real number because we don't have restrictions.
c.
[tex]-\text{ l x-5l +1}[/tex]We have an absolute value but x can be any real number.
d.
[tex]\frac{1}{2}\sqrt[3]{x+6}[/tex]The cube root can be used for real numbers, so the function can take for x all real numbers.
The only function that doesn't have a domain of all real numbers is option a.
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