Okay, here we have this:
Considering the provided information, we are going to calculate the requested maximum possible number of vases, so we obtain the following:
We obtain that the correct answer is option B (4 glasses), because:
From the given information we are left with the following equation:
[tex]\begin{gathered} v^2+v=20 \\ v^2+v-20=0 \\ (v-4)(v+5)=0 \\ v-4=0,v+5=0 \\ v=4,v=-5 \end{gathered}[/tex]
Finally, since we are looking for a quantity, we are only left with the positive value of v, which tells us that the maximum number of glasses with 20 pints is equal to 4 glasses. Then the correct answer is the option B.
