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A line passes through the points (9,-4) and (10, -3). What is its equation in slope-interceptform?Write your answer using integers, proper fractions, and improper fractions in simplest form.

A Line Passes Through The Points 94 And 10 3 What Is Its Equation In SlopeinterceptformWrite Your Answer Using Integers Proper Fractions And Improper Fractions class=

Sagot :

Answer:

y = x - 13

Explanation:

The equation of a line that passes through two points (x1, y1) and (x2, y2) is:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is calculated as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

So, replacing (x1, y1) by (9, -4) and (x2, y2) by (10, -3), we get that m is equal to:

[tex]m=\frac{-3-(-4)}{10-9}=\frac{-3+4}{1}=\frac{1}{1}=1[/tex]

Then, the equation of the line is:

[tex]\begin{gathered} y-(-4)=1(x-9) \\ y+4=x-9 \end{gathered}[/tex]

Finally, to write the equation in slope-intercept form, we need to solve for y, so:

[tex]\begin{gathered} y+4-4=x-9-4 \\ y=x-13 \end{gathered}[/tex]

So, the answer is:

y = x - 13

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