Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Charle's Law states that the volume varies directly with it's temperature and can be expressed as :
[tex]V=kT[/tex]Where V is the volume, T is the temperature and k is some constant
From the given problem, we have :
V1 = 0.8 liters
T1 = 400 degrees
V2 = 0.3 liters
Since k is a constant,
[tex]V_1=kT_1[/tex][tex]V_2=kT_2[/tex]We can express both equation as k = V/T
[tex]k=\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]Substitute the given values to the formula :
[tex]\frac{0.8}{400}=\frac{0.3}{T_2}[/tex]Then solve for the value of T2 :
Simplify the equation by multiplying 400T2 to both sides of the equation :
[tex](400T_2)\times\frac{0.8}{400}=(400T_2)\times\frac{0.3}{T_2}[/tex][tex]0.8T_2=120[/tex][tex]T_2=\frac{120}{0.8}=150[/tex]Therefore the answer is 150 degrees
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
