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Sagot :
Charle's Law states that the volume varies directly with it's temperature and can be expressed as :
[tex]V=kT[/tex]Where V is the volume, T is the temperature and k is some constant
From the given problem, we have :
V1 = 0.8 liters
T1 = 400 degrees
V2 = 0.3 liters
Since k is a constant,
[tex]V_1=kT_1[/tex][tex]V_2=kT_2[/tex]We can express both equation as k = V/T
[tex]k=\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]Substitute the given values to the formula :
[tex]\frac{0.8}{400}=\frac{0.3}{T_2}[/tex]Then solve for the value of T2 :
Simplify the equation by multiplying 400T2 to both sides of the equation :
[tex](400T_2)\times\frac{0.8}{400}=(400T_2)\times\frac{0.3}{T_2}[/tex][tex]0.8T_2=120[/tex][tex]T_2=\frac{120}{0.8}=150[/tex]Therefore the answer is 150 degrees
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