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Sagot :
SOLUTION
Let the cars weigh 3. 6 tons each
Let the trucks weigh 7. 5 tons each
Let c be the number of cars
Let t be the number of trucks
3. 6 c + 7. 5 t = 21600
a) when t = 480
3. 6 c + 7. 5 ( 480 ) = 21600
3. 6 c + 3600 = 21600
3. 6 c = 21600 - 3600
3.6 c = 18000
Divide both sides by 3. 6, we have:
c = 18000 / 3. 6
c = 5000 cars
b ) when t = 1500
3. 6 c + 7. 5 ( 1500 ) = 21600
3. 6 c + 11250 = 21600
3. 6 c = 21600 - 11250
3. 6 c = 10350
Divide both sides by 3.6 , we have:
c = 2875 cars
c ) when t = 2736
3. 6 c + 7. 5 ( 2736 ) = 21600
3. 6 c + 20520 = 21600
3.6 c = 21600 - 20520
3.6 c = 1040
Divide both sides by 3. 6, we have :
c = 300 cars
d) when t = t trucks
3. 6 c + 7. 5 t = 21600
3. 6 c = 21600 - 7. 5 t
c = 1 / 3. 6 ( 21600 - 7.5 t )
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