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Sagot :
Answer:
$9,330.35
Explanation:
We'll use the below compound interest formula to solve the problem;
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where A = the future amount = $11,000
P = the starting amount(the principal)
r = the interest rate in decimal = 5.5% = 5.5/100 = 0.055
n = number of compounding periods = 12
t = time periods = 3 years
So let's go ahead and substitute the above values into our equation;
[tex]11000=P(1+\frac{0.055}{12})^{12\ast3}[/tex]We can then evaluate and find P;
[tex]\begin{gathered} 11000=P(1.004583)^{36} \\ 11000=P(1.178949) \\ P=\frac{11000}{1.178949} \\ \therefore P=9,330.35 \end{gathered}[/tex]So the amount that should be deposited is $9,330.35
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