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125 125 A. O B. 25 C. 11.2 D. 5

Sagot :

Cube root

We want to find a number that multiplied three times by itself equals 125 in order to find

[tex]\sqrt[3]{125}[/tex]

We know that

25 · 5 = 125

and

5 · 5 = 25

Then

[tex]\begin{gathered} 5\cdot5\cdot5=125 \\ 5^3=125 \\ \end{gathered}[/tex]

Then

[tex]\begin{gathered} \sqrt[3]{125}=\sqrt[3]{5^3} \\ \sqrt[3]{125}=5 \end{gathered}[/tex]

Answer: D. 5

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