Answered

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A buffer solution is prepared by adding 275 mL of .676 M of HCl to 500 mL of .525M sodium acetate. What is the pH of this buffer?

Sagot :

Answer:

-6.15

Explanations

The formula for calculating the pH of a buffer is expressed as

[tex]pH=pka+log\frac{[salt]}{[acid]}^[/tex]

pka of the hydrochloric acid = -6.3

Calclate the moles of the HCl and sodium acetate

[tex]\begin{gathered} moles=molarity\times volume \\ moles\text{ of HCl=0.676M}\times0.275 \\ moles\text{ of HCl=0.1859moles} \end{gathered}[/tex]

Calculate the moles of sodium acetate (salt)

[tex]\begin{gathered} moles\text{ of sodium acetate=0.525M}\times0.500 \\ moles\text{ of sodium acetate=0.2625moles} \end{gathered}[/tex]

Substitute the given parameters into the formula

[tex]\begin{gathered} pH=pka+log\frac{[0.2625\text{/v}]}{[0.1859\text{/v}]} \\ pH=-6.3+log1.4121 \\ pH=-6.3+0.1498 \\ pH=-6.1502 \end{gathered}[/tex]

Hence the pH of this buffer is approximately -6.15

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