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Sagot :
Given:
• Diameter, D = 0.00620 m
,• Wavelength, λ = 525 nm
,• Distance, x = 50.0 m
Let's find the closest detail it could possibly resolve.
Let's apply the Angular separation formula:
[tex]\theta=\frac{1.22\lambda}{D}[/tex]Thus, we have:
[tex]\begin{gathered} \theta=\frac{1.22*525\times10^{-9}}{0.00620} \\ \\ \theta=\frac{6.405\times10^{-7}}{0.00620} \\ \\ \theta=1.033\times10^{-4\text{ }}rad \end{gathered}[/tex]Now, to find the distance which is the closest detail, we have:
[tex]\begin{gathered} d=\theta *x \\ \\ d=1.033\times10^{-4}*50.0 \\ \\ d=0.005165\text{ m} \end{gathered}[/tex]The closest detail it could possibly resolve is at 0.005165 meters
• ANSWER:
0.005165 m
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