Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

We need help with this question. Sorry but it’s taken from a French math book, so we had to translate the it.ABC is a triangle that has: ACB = 86° and ABC = 37°.The bisector of angle ACBIntersects segment [AB] at M.Calculate angles BMC and AMCThis is what we have done so far:BCM-MBC=(86:2)-37=43-37So, 180-6=174BMC = 180 - 6 = 174

Sagot :

We want to calculate angles BMC and AMC, as you can observe, these angles are supplementary.

Thus using triangle relations, we start by calculating angle BMC.

We can agree that;

[tex]\begin{gathered} \angle CBM+\angle MCB+\angle BMC=180 \\ \angle CBM=37 \\ \angle MCB=\frac{86}{2}=43 \\ \angle BMC=180-43-37=100^o \end{gathered}[/tex]

And;

[tex]\begin{gathered} \angle BMC+\angle AMC=180 \\ 100+\angle AMC=180 \\ \angle AMC=80^o \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} \angle AMC=80^0 \\ \angle BMC=100^o \end{gathered}[/tex]

View image KleoR636490
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.