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Use the diagram below where ABCD is a parallelogram withright angle at

Use The Diagram Below Where ABCD Is A Parallelogram Withright Angle At class=

Sagot :

True statements: B, C, E, F

Explanation:

Right angle is at ∠BAD

∠BAD = 90 degree

Opposite angles of a parallelogram are equal

∠BAD = ∠BCD

∠ABC = ∠ADC

a) The diagonals bisect each other

Since angle on a straight line is 180 degrees

By bisecting each other, the angles are divided ito two equal parts.

∠BOC = 180/2 = 90 degree

Hence, ∠BOC is not 45 degrees

b) Since ∠BAD = 90 degree

And the diagonal bisects the vertex, the angles are divided into two equal parts

∠BAC = 90/2 = 45

∠BAC = 45 degrees

c) ∠B is the same for both

∠ABO is congruent to ∠DBA

d) From the explanation above, ∠ABC = ∠ADC = 90 degrees

Since ∠B is 90 degrees, the triangle is right angled not scalene

e) AB corresponds to DC

BD corresponds to CA

AD corresponds to AD (reflexive property)

Since the three sides of triangle ABD corresponds to the three sides of triangle DCA

Hence, triangle ABD is congruent to triangle DCA

f) ∠O = 90 degree

∠A = 45 degree

∠ D = 45 degree

In triangle AOD, two angles are equal (90 degree). Hence, triangle AOD is an isosceles triangle

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