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when the corporate playing the graft of a linear equation goes up three units for every two units it goes to the right. One point on the graph is (1. 1) which points is also on the graft.

Sagot :

Consider that on a coordinate plane-xy, the x-values increase from left to right, and y-values increase from bottom to up.

Given that the linear graph passes through (1,1).

It is given that the graph goes 3 units up for every 2 units right. This can also be understood as the graph goes 3 units down for every 2 units left.

From the point (1,1), the x-value corresponding to 2 units left is given by,

[tex]\begin{gathered} x=1-(2) \\ x=-1 \end{gathered}[/tex]

Similarly, from the point (1,1), the y-value corresponding to 3 units down is given by,

[tex]\begin{gathered} y=1-(3) \\ x=-2 \end{gathered}[/tex]

So the point (-1,-2) must also lie on the same linear graph.

Therefore, option (b) is the correct choice.

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