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Sagot :
Answer:
[tex]22.386L[/tex]Explanations:
In order to get the required volume of the gas, we will use the ideal gas equation expressed as:
[tex]PV=\text{nRT}[/tex]P is the pressure of the gas (in atm)
V is the volume of the gas (in L)
n is the number of moles
R is the Gas constant
T is the temperature of the gas
Given the following parameters:
[tex]\begin{gathered} P=1\text{atm} \\ T=273K \\ n=1\text{mole} \\ R=0.082Latm/moleK \\ V=\text{?} \end{gathered}[/tex]Substitute the given parameters into the formula to get the volume:
[tex]\begin{gathered} V=\frac{\text{nRT}}{P} \\ V=\frac{1\cancel{\text{mole}}\times0.082\frac{L\cdot\cancel{\text{atm}}}{\cancel{\text{molK}}}\times273\cancel{K}}{1\cancel{\text{atm}}} \\ V=\frac{1\times0.082L\times273}{1} \\ V=22.386L \end{gathered}[/tex]Hence the volume of a gas at 273K be if I have 1 mole of the gas at 1 atm is 22.386L
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