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Sagot :
Note that we are told that the standard says that the maximum power consumption should be 11.1kWh per square foot.
So, for any household it must happen that if we take its maximum power consumption and divide it by its area, we should get the given rate.
So, let x be the maximum power consumption. Since the area is 2460 square foot, we have that
[tex]\frac{x}{2460}=11.1[/tex]So if we multiply both sides by 2460, we get that
[tex]x=2460\cdot11.1=27306[/tex]So the maximum power consumption of the house hould is 27306 kWh.
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