Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
We are given the following equation
[tex]-3\mleft(x-14\mright)+9x=6x+42[/tex]Let us solve the equation for x.
Step 1:
Multiply the term -3 with the terms in the parenthesis.
[tex]\begin{gathered} -3(x-14)+9x=6x+42 \\ -3x+42+9x=6x+42 \end{gathered}[/tex]Step 2:
Simplify the terms on the left-hand side of the equation
[tex]\begin{gathered} -3x+42+9x=6x+42 \\ 42+6x=6x+42 \end{gathered}[/tex]Step 3:
Combine the like terms together.
[tex]\begin{gathered} 42+6x=6x+42 \\ 42-42=6x-6x \\ 0=0 \end{gathered}[/tex]This means that this equation has an infinite number of possible solutions.
If you notice the left and right side of the equation are exactly the same.
[tex]42+6x=6x+42[/tex]This means that whatever value of x you put into this equation, the equation will always be satisfied.
Try substituting some values for x.
[tex]\begin{gathered} 42+6(1)=6(1)+42 \\ 42+6=6+42 \\ 48=48 \end{gathered}[/tex][tex]\begin{gathered} 42+6(-2)=6(-2)+42 \\ 42-12=-12+42 \\ 30=30 \end{gathered}[/tex]Hence, the given equation has an infinite number of possible solutions.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
