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A 300K gas in a 3L container is transfered to a 10L container. What is the resulting temperature in K?

Sagot :

Because we are looking for the temperature change caused by a volume change at constant pressure, this is for Charles’s law. Taking V1 and T1 as the initial values, we can use the following equation:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

We are given:

T1 = 300 K

V1 = 3 L

V2 = 10 L

(3L/300K) = (10L/T2)

T2 = 10L/(3L/300K)

T2 = 1000 K)

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