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please see the image and help with this homework problem. thank you!

Please See The Image And Help With This Homework Problem Thank You class=

Sagot :

we have the function

[tex]E=\sin \frac{\pi}{14}t[/tex]

Part a

For t=7

substitute in the given function

[tex]\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}[/tex]

For t=14

[tex]\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}[/tex]

For t=21

[tex]\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}[/tex]

For t=28

[tex]\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}[/tex]

For t=35

[tex]\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}[/tex]

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

the period is 28 days

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