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Sagot :
Let
t -----> number of hours
P -----> price of the bike rental
so
Part a) The hourly charge is $___ per hour for the first 3 hours
Find the slope of the line in the interval (0,3)
we take the points
(0,8) and (3,20)
m=(20-8)/(3-0)
m=12/3
m=4
that means
the hourly charge is $4 per hour
Part b) The rate then drops to $___ per hour until the end of the 6th hour
Find the slope of the line in the interval (3,6)
we take the points
(3,20) and (6,26)
m=(26-20)/(6-3)
m=6/3
m=2
that means
The rate then drops to $2 per hour until the end of the 6th hour
Part c) The hourly rate drops further to $___ per hour between the 6th and 10th hours
Find the slope of the line in the interval (6,10)
we have the points
(6,26) and (10,30)
m=(30-26)/(10-6)
m=4/4
m=1
therefore
The hourly rate drops further to $1 per hour between the 6th and 10th hours
Part d) The maximum price of the bike rental is $
Looking at the graph
For
[tex]t\ge10\text{ h}[/tex]the value of P=$30
so
The maximum price of the bike rental is $30
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