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Lisa's teacher wrote the following equations of a translations the board: x' = 2-x and y'= y - 3 wx'hat would be the translation of point K(-3, -1)a. ( 5,-2)b. (-1, -4)c. (-1, -2)d. (5, -4)

Sagot :

Answer:

d. (5,-4)

Explanation:

Given:

x' = 2-x

y'= y - 3

Point K(-3, -1)

Based on the given point K(-3, -1), the values of coordinates are:

x= -3

y= -1

We plug in x = -3 into x' = 2-x. So,

[tex]\begin{gathered} x^{\prime}=2-x \\ ^{}=2-(-3) \\ ^{}=2+3_{} \\ \text{Calculate} \\ x^{\prime}=5 \end{gathered}[/tex]

We plug in y = -1 into y'= y - 3.

[tex]\begin{gathered} y^{\prime}=y-3 \\ =-1-3 \\ \text{Calculate} \\ y^{\prime}=-4 \end{gathered}[/tex]

Therefore, the translation of point K(-3, -1) is (5,-4).