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Find the length of the shorter leg in a 30 - 60 - 90 triangle where the hypotenuse is 10 units.

Find The Length Of The Shorter Leg In A 30 60 90 Triangle Where The Hypotenuse Is 10 Units class=

Sagot :

Hello!

First, let's draw this right triangle to understand better the problem:

Analyzing the draw, we can use the Property of Sine:

[tex]\sin (30\degree)=\frac{\text{ opposite}}{\text{ hypotenuse}}[/tex]

Remember that sin(30º) = 1/2.

Let's replace the values in the formula and solve it:

[tex]\frac{1}{2}=\frac{\text{ x}}{\text{ 1}0}[/tex]

Multiplying across:

[tex]\begin{gathered} (2\cdot x)=(1\cdot10) \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]

Right answer: D. 5 units.

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